SOLUTION: Two mechanics worked on a car. The first mechanic worked for 20 hours, and the second mechanic worked for 15 hours. Together they charged a total of $2250 . What was the

Algebra ->  Coordinate Systems and Linear Equations -> SOLUTION: Two mechanics worked on a car. The first mechanic worked for 20 hours, and the second mechanic worked for 15 hours. Together they charged a total of $2250 . What was the      Log On


   



Question 1090193: Two mechanics worked on a car. The first mechanic worked for
20
hours, and the second mechanic worked for
15
hours. Together they charged a total of
$2250
. What was the rate charged per hour by each mechanic if the sum of the two rates was
$125
per hour?

Found 2 solutions by ikleyn, josgarithmetic:
Answer by ikleyn(52775) About Me  (Show Source):
You can put this solution on YOUR website!
.
Two mechanics worked on a car. The first mechanic worked for 20 hours, and the second mechanic worked for 15 hours.
Together they charged a total of $2250.
What was the rate charged per hour by each mechanic, if the sum of the two rates was
$125 per hour?
~~~~~~~~~~~~~~~

Let x be the rate of the first mechanic.
Then the rate of the second mechanic is (125 - x) dollars.

The "amount" equation is

20x + 15*(125-x) = 2250  dollars.


Simplify and solve for x:

20x + 1875 - 15x = 2250  ====>

5x = 2250 - 1875 = 375  ====>  x = 375%2F5 = 75.


Thus the first mechanic's rate is $75 per hour.


Then the second mechanic's rate is $125 - $75 = $50 per hour.

Solved.


Answer by josgarithmetic(39616) About Me  (Show Source):
You can put this solution on YOUR website!
system%2820x%2B15y=2250%2Cx%2By=125%29

4x%2B3y=450
4x%2B3%28125-x%29=450
4x%2B375-3x=450
highlight%28x=75%29-------rate for first mechanic
-
highlight%2850%29--------rate for second mechanic