SOLUTION: A car traveled for a total of 566 miles over the course of 8 hours on two highways. On the first highway, the car traveled at an average speed of 57 miles per hour. On the se

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Question 1090185: A car traveled for a total of 566 miles over the course of 8 hours on two highways. On the first highway, the car traveled at an average speed of 57 miles per hour. On the second highway, it traveled at an average speed of 79 miles per hour. For how many hours was the car on the first highway?
I did my equation and i got x,y but then what do i do I'm confused?
i got x as -33 and y as -25 i don't know if that right

Found 2 solutions by Fombitz, MathTherapy:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
1.57%2At%5B1%5D%2B79%2At%5B2%5D=566
2.t%5B1%5D%2Bt%5B2%5D=8
Multiply 2 by 57 and subtract from 1,
57t%5B1%5D%2B79t%5B2%5D-57t%5B1%5D-57t%5B2%5D=566-456
22t%5B2%5D=110
Take it from there and solve for t%5B2%5D.
Then use either equation to solve for t%5B1%5D.

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

A car traveled for a total of 566 miles over the course of 8 hours on two highways. On the first highway, the car traveled at an average speed of 57 miles per hour. On the second highway, it traveled at an average speed of 79 miles per hour. For how many hours was the car on the first highway?
I did my equation and i got x,y but then what do i do I'm confused?
i got x as -33 and y as -25 i don't know if that right
Correct answer: It was on the 1st highway for: highlight_green%28matrix%281%2C2%2C+3%2C+hours%29%29, done as follows:
Let the time spent on 1st highway be T
Then time spent on 2nd highway = 8 - T
We then get the following DISTANCE equation: 57T + 79(8 - T) = 566
Solve this for T, the time spent on the 1st highway.