SOLUTION: Hi. Can someone please help me with this? \frac{a + 3}{a + 1} : \frac{a^{2} - 2 a - 15}{a^{2} + 5 a + 6} Thank You.

Algebra ->  Rational-functions -> SOLUTION: Hi. Can someone please help me with this? \frac{a + 3}{a + 1} : \frac{a^{2} - 2 a - 15}{a^{2} + 5 a + 6} Thank You.      Log On


   

Question 1090159: Hi. Can someone please help me with this?
\frac{a + 3}{a + 1} : \frac{a^{2} - 2 a - 15}{a^{2} + 5 a + 6}
Thank You.
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Denominators cannot equal zero so,
a%2B1=0
a=-1
and
a%5E2%2B5a%2B6=%28a%2B2%29%28a%2B3%29
a%2B2=0
a=-2
and
a%2B3=0
a=-3
These are all restricted values.
a%3C%3E-1
a%3C%3E-2
a%3C%3E-3