SOLUTION: The curves y=x^3+4 and y=3x+4 intersect at x=1 and x=2. True or False ?

Algebra ->  Square-cubic-other-roots -> SOLUTION: The curves y=x^3+4 and y=3x+4 intersect at x=1 and x=2. True or False ?       Log On


   



Question 1090077: The curves y=x^3+4 and y=3x+4 intersect at x=1 and x=2. True or False ?

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

The curves y=x%5E3%2B4 and y=3x%2B4
x%5E3%2B4=3x%2B4...solve for x
x%5E3%2B4-3x-4=0
x%5E3-3x=0
x%28x%5E2-3%29=0
solutions:
x=0
x%5E2-3=0=>x%5E2=3=>x=sqrt%283%29 or x=-sqrt%283%29
+graph%28+600%2C+600%2C+-10%2C+10%2C+-10%2C+10%2Cx%5E3%2B4%2C+3x%2B4%29+

The curves y=x%5E3%2B4 and y=3x%2B4 intersect at x=1 and x=2 is +False statement.