SOLUTION: Customers of a phone company can choose between two service plans for long distance calls. The first plan has a $17 monthly fee and charges and additional $0.08 for each minute of

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: Customers of a phone company can choose between two service plans for long distance calls. The first plan has a $17 monthly fee and charges and additional $0.08 for each minute of       Log On


   



Question 1089986: Customers of a phone company can choose between two service plans for long distance calls. The first plan has a $17 monthly fee and charges and additional $0.08 for each minute of calls. The second plan has a
$9 monthly fee and charges an additional $0.13 for each minute of calls. For how many minutes of calls will the costs of the two plans be equal?

Answer by EMStelley(208) About Me  (Show Source):
You can put this solution on YOUR website!
We need to start by setting up an equation for the monthly cost of each plan. To do this we need to name a variable for the number of minutes, let's say x. Let's call the first plan A and the second plan B. Then if the first plan has a $17 monthly fee and $0.08 per minute, we can represent that as:
A+=+17+%2B+0.08x
The second plan is $9 monthly plus $0.13 per minute, so
B+=+9+%2B+0.13x
The question is asking when they will be the same, so we literally set them equal to each other.
17+%2B+0.08x+=+9+%2B+0.13x
Subtracting 9 to the left, and 0.08x to the right, we have
8+=+0.05x
Lastly, by dividing both sides by 0.05, we get
x+=+160
So the cost of the two plans will be equal when the number of minutes is 160.