SOLUTION: Stacey observed that it took w women 10 days to do j jobs. Then, she calculated how long it would take n more women to do 28 more jobs. What was her answer?
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Question 1089976: Stacey observed that it took w women 10 days to do j jobs. Then, she calculated how long it would take n more women to do 28 more jobs. What was her answer? Found 3 solutions by josmiceli, ankor@dixie-net.com, MathTherapy:Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website! women - - days - - jobs
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w - - - - - - 10 - - - - - - - - - j
1 - - - - - - - 10w - - - - - - - - j
n + w - - - - - (10w)/( n+w ) - - j
n + w - - ( 10w ) / ( j*( n+w )) - - 1
n + w - - ( (10w)*( j+28 ) ) / ( j*( n+w )) - - j + 28
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( (10w)*( j+28 ) ) / ( j*( n+w )) days
get another opinion on this
I'm not 100% sure
You can put this solution on YOUR website! Stacey observed that it took w women 10 days to do j jobs.
Find how many man-days for 1 job
Then, she calculated how long it would take n more women to do 28 more jobs. What was her answer? * =
You can put this solution on YOUR website! Stacey observed that it took w women 10 days to do j jobs. Then, she calculated how long it would take n more women to do 28 more jobs. What was her answer?
kj = 10w ------- Cross-multiplying ------ Adding n MORE women, and 28 MORE jobs ---------- Cross-multiplying
T, or time =
