Solve each of the following systems by graphing.
2x - y = 4
2x - y = 6
Get two points on the first line.
Plot them and draw a line through them.
Get two points on the second line.
Plot them and draw a line through them.
Identify the coodinates of the point where the two lines cross.
Get two points on the first line whose equation is 2x - y = 4
Arbitrarily pick any convenient number to substitute
for either letter. I think I will first choose 0 to substitute
for x. I chose 0 simply because it is easy. I could have chosen
any other number, and for either letter. So we substitute x = 0
2x - y = 4
2(0) - y = 4
0 - y = 4
-y = 4
-1y = 4
y =
y = -4, so one point on the first line is (x, y) = (0,-4)
Now for the second point on the first line, I think I will choose 0 to substitute for y. Again I chose 0 simply because it is easy. I could
have chosen any other number, and for either letter. So we substitute
y = 0
2x - y = 4
2x -(0) = 4
2x = 4
x =
x = 2, so another point on the first line is (x, y) = (2, 0)
Plot the two points (0, -4) and (2, 0):
Draw a straight line through them:
Get two points on the second line, whose equation is 2x - y = 6
Arbitrarily pick any convenient number to substitute
for either letter. I will again first choose 0 to substitute
for x. Again I chose 0 simply because it is easy. I could have chosen
any other number, and for either letter. So we substitute x = 0
2x - y = 6
2(0) - y = 6
-y = 6
y =
y = -6, so another point on the second line is (x, y) = (0, -6)
Now for the second point on the second line, I will again choose 0 to
substitute for y. Again I chose 0 simply because it is easy. I could
have chosen any other number, and for either letter. So we substitute
y = 0
2x - y = 6
2x -(0) = 6
2x = 6
x =
x = 3, so another point on the first line is (x, y) = (3, 0)
Plot the two points (0, -4) and (3, 0):
so another point on the second line is (x, y) = (4, 0)
Plot the two points (0, -6) and (3, 0):
Draw a straight line through them:
Oh,oh! These two lines are parallel and therefore
they do not intersect, so there is no solution.
This type of system is called "inconsistent".
Edwin