SOLUTION: A Cashier working alone serves 20 clients in 1 hour. A second Cashier serves the same number of clients in 40 minutes. What time will they need serving the 20 clients if they work
Question 1089802: A Cashier working alone serves 20 clients in 1 hour. A second Cashier serves the same number of clients in 40 minutes. What time will they need serving the 20 clients if they work both? Found 2 solutions by josgarithmetic, ikleyn:Answer by josgarithmetic(39620) (Show Source):
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A Cashier working alone serves 20 clients in 1 hour. A second Cashier serves the same number of clients in 40 minutes.
What time will they need serving the 20 clients if they work both?
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In this problem, let us call this work, serving 20 clients, as "one job".
Then the first cashier makes of the job per minute. It is his rate of work.
The second cashier makes of the job per minute. It is his rate of work.
When they work together, their combined rate of work is the sum of individual rates, i.e. = = = .
Thus we get that the two cashiers, working together, make of the job per minute.
Now it is clear to you that it will take 24 minutes for both to serve 20 clients.
The problem is solved.