Question 1089797: An object which is vertically projected or falls from the sky has a velocity of v and is given by: v = -32t + vo, where v is the velocity in feet/sec, t is the time in seconds, and vo is the initial velocity in feet per second. If the initial velocity is 159 feet/sec, and the velocity v is in the range of 25 < v < 53, find the time interval t.
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! An object which is vertically projected or falls from the sky has a velocity of v and is given by: v = -32t + vo, where v is the velocity in feet/sec, t is the time in seconds, and vo is the initial velocity in feet per second. If the initial velocity is 159 feet/sec, and the velocity v is in the range of 25 < v < 53, find the time interval t.
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v = -32t + vo
v = -32t + 159
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v = -32t + 159 = 25
Solve for t.
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v = -32t + 159 = 53
Solve for t.
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