SOLUTION: 21. (See Week 4 Lecture page “Solving Rational Inequalities” for a starting point.)
Suppose that a factory’s cost (in dollars) for making x cars is
C(x) = 7020x + 8460
Then
Algebra ->
Polynomials-and-rational-expressions
-> SOLUTION: 21. (See Week 4 Lecture page “Solving Rational Inequalities” for a starting point.)
Suppose that a factory’s cost (in dollars) for making x cars is
C(x) = 7020x + 8460
Then
Log On
Question 1089705: 21. (See Week 4 Lecture page “Solving Rational Inequalities” for a starting point.)
Suppose that a factory’s cost (in dollars) for making x cars is
C(x) = 7020x + 8460
Then the average cost per car is
𝐶′(𝑥)= 7020𝑥 + 8460 /𝑥
How many cars must the factory make each day to ensure the average cost per car is no more than $7200?
