SOLUTION: If the center of circle x^2 +y^2 -4x-6y-3 =0 is (h,k) and the radius is r, then h+k+r=?

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Question 1089604: If the center of circle x^2 +y^2 -4x-6y-3 =0 is (h,k) and the radius is r, then h+k+r=?
Found 2 solutions by Fombitz, MathLover1:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Complete the square in x and y to solve for h,k, and r.
x%5E2-4x%2By%5E2-6y=3
%28x%5E2-4x%2B4%29%2B%28y%5E2-6y%2B9%29=3%2B4%2B9
%28x-2%29%5E2%2B%28y-3%29%5E2=16
So,
h=2
k=3
r=4
Take it from there.

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
x%5E2+%2By%5E2+-4x-6y-3+=0 is (h,k) and the radius is r, then h%2Bk%2Br=?
x%5E2+-4x+%2By%5E2-6y-3+=0
%28x%5E2+-4x%2B2%5E2%29-2%5E2+%2B%28y%5E2-6y%2B3%5E2%29-3%5E2=3
%28x+-2%29%5E2-4+%2B%28y-3%29%5E2-9=3
%28x+-2%29%5E2+%2B%28y-3%29%5E2=3%2B4%2B9
%28x+-2%29%5E2+%2B%28y-3%29%5E2=16
%28x+-2%29%5E2+%2B%28y-3%29%5E2=4%5E2
=> h=2, k=3, r=4
then h%2Bk%2Br=2%2B3%2B4=9