SOLUTION: The path of the ball is modeled by the function h(x)=2.7x - 136(x^2)/(v^2) + 3.5 where h is the height of the ball above the floor, x is the forward distance of the ball in fron

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Question 1089586: The path of the ball is modeled by the function
h(x)=2.7x - 136(x^2)/(v^2) + 3.5
where h is the height of the ball above the floor, x is the forward distance of the ball in front of the foul line, and v is the initial velocity with which the ball is shot (ft/s).
Determine the initial velocity with which the ball must be shot in order for the ball to go through the hoop. The center of the hoop is 10 feet above the floor and 15 feet in front of the foul line.
Answer by ikleyn(52908) About Me  (Show Source):
You can put this solution on YOUR website!
.
Substitute h = 10 and x = 15 into the equation and then solve for v.