SOLUTION: Hey please help me with this question: An orange cost 8 cents more than an apple. If I buy 7 apples and 8 oranges the total cost is $4.24. Find the cost of one Apple.

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: Hey please help me with this question: An orange cost 8 cents more than an apple. If I buy 7 apples and 8 oranges the total cost is $4.24. Find the cost of one Apple.      Log On


   

Question 1089567: Hey please help me with this question: An orange cost 8 cents more than an apple. If I buy 7 apples and 8 oranges the total cost is $4.24. Find the cost of one Apple.
Found 2 solutions by josgarithmetic, math_helper:
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
Prices p and p+0.08

7p%2B8%28p%2B0.08%29=4.24
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p, price of Apple, 0.24 dollars each
price of Orange, 0.32 dollars each

Answer by math_helper(2461) About Me  (Show Source):
You can put this solution on YOUR website!
Let a = cost of apple, in cents
Let r = cost of orange, in cents
r = a + 8 (1)
7a + 8r = 424 (2)
Substitute "a+8" from (1) into (2):
7a + 8(a+8) = 424
15a + 64 = 424
15a = 360
a=24 —> r=24+8 = 32
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Ans: Apples cost 24 cents each (and Oranges cost 32 cents each.)
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Check:
32 = 24+8 (ok)
7(24) + 8(32) = 168 + 256 = 424 = $4.24 (ok)