SOLUTION: A ball is projected directly upward from and initial height of 200 feet with an initial velocity of 120 feet per second. After how many seconds does the ball reach its maximum heig

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Question 1089530: A ball is projected directly upward from and initial height of 200 feet with an initial velocity of 120 feet per second. After how many seconds does the ball reach its maximum height? What is this height?
Found 2 solutions by jorel1380, ikleyn:
Answer by jorel1380(3719) About Me  (Show Source):
You can put this solution on YOUR website!
The equation for this ball's movement would be h(t)=-16t²+120t+200, where t is time and h(t) is the ball's height at any given t. The ball will reach its maximum height at t=-b/2a, where b is the initial velocity(120), and a is the acceleration (-16a). In this case, -b/2a=-120/-32=3.75 seconds before the ball reaches its maximum height. Then:
-16(3.75²)+120(3.75)+200=425 ft is the ball's maximum height.
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Answer by ikleyn(52786) About Me  (Show Source):
You can put this solution on YOUR website!
.
In this site, there is a bunch of lessons on a projectile thrown/shot/launched vertically up
    - Problem on a projectile moving vertically up and down
    - Problem on an arrow shot vertically upward
    - Problem on a ball thrown vertically up from the top of a tower
    - Problem on a toy rocket launched vertically up from a tall platform


Also,  you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this textbook under the topic "Projectiles launched/thrown and moving vertically up and dawn".