SOLUTION: One number is 10 less than a second number. Twice the second number is 59 more than 5 times the first. Find the two numbers?

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Question 1089494: One number is 10 less than a second number. Twice the second number is 59 more than 5 times the first. Find the two numbers?
Answer by math_helper(2461) About Me  (Show Source):
You can put this solution on YOUR website!
Let n = the first number
Let m = the 2nd number
+n+=+m+-+10+ —> +m-n+=+10+ (1)
+2m+=+59%2B5n+ —> +2m-5n+=+59+ (2)
2*(1) —> +2m+-+2n+=+20+
subtract (2) +2m-5n+=+59+
resulting in: ++3n+=+-39+
Ans: +highlight%28n+=+-13%29 and +highlight%28m+=+-3+%29
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Check: -13 is 10 less than -3 (ok)
2(-3) = -6
59 + 5(-13) = 59+(-65) = -6 (ok)