SOLUTION: The number of ways in which 10 persons can go in two boats, so that there may be 5 on each boat,supposing that two particular persons will not go in the same boat is?

Algebra ->  Permutations -> SOLUTION: The number of ways in which 10 persons can go in two boats, so that there may be 5 on each boat,supposing that two particular persons will not go in the same boat is?      Log On


   

Question 1089205: The number of ways in which 10 persons can go in two boats, so that there may be 5 on each boat,supposing that two particular persons will not go in the same boat is?
Answer by ikleyn(52817) About Me  (Show Source):
You can put this solution on YOUR website!
.
= 2%2AC%5B8%5D%5E4 = 2%2A%288%2A7%2A6%2A5%29%2F%281%2A2%2A3%2A4%29 = 2*70 = 140.

You place these 2 enemies in different boats by 2 ways,

and then you select 4 of 8 to place in one boat; then the remaining 4 are automatically assigned for the other boat.

On combinations, see the lessons
    - Introduction to Combinations
    - PROOF of the formula on the number of Combinations
    - Problems on Combinations
    - OVERVIEW of lessons on Permutations and Combinations
in this site.

Also,  you have this free of charge online textbook in ALGEBRA-II in this site
    - ALGEBRA-II - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic  "Combinatorics: Combinations and permutations".