SOLUTION: If x>0 and x^y (x^1/2)=x^3/8 A)1/2 B)1/3 C)1/4 D)-1/8
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Question 1089179
:
If x>0 and x^y (x^1/2)=x^3/8
A)1/2
B)1/3
C)1/4
D)-1/8
Answer by
stanbon(75887)
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If x>0 and x^y (x^1/2)=x^3/8. What is the value of "y"?
x^(y+(1/2)) = x^(3/8)
y+(1/2) = 3/8
y = -1/8
Cheers,
Stan H.
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A)1/2
B)1/3
C)1/4
D)-1/8