SOLUTION: Find the surface area of a regular triangular pyramid with a height of 18 and base length 8.

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Question 1089151: Find the surface area of a regular triangular pyramid with a height of 18 and base length 8.
Answer by MathLover1(20849) About Me  (Show Source):
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A pyramid with a triangle as a base is a triangular pyramid. Since the base is a triangle and a triangle has three sides, a triangular pyramid has three triangular faces.
Thus, the surface area of a triangular pyramid is the area of all of its faces and base combined. When we have a regular triangular pyramid, all of the faces of the pyramid have the same area. Therefore, the surface area of a regular triangular pyramid can be found by adding the area of the base to 3 times the area of one of the faces. That is,
SA+=+A+%2B+3a+where A is the area of the pyramid's base, and a is the area of one of the pyramid's faces.
Therefore, our surface area formula becomes:

SA+=+A+%2B+3%281%2F2%29bl
SA+=+A+%2B+%283%2F2%29bl, whereb is the base of one of the pyramid's faces, which is also the length of one of the sides of the pyramid's base, and l is the slant height of one of the pyramid's faces

if given: the surface area of a regular triangular pyramid with a height of 18 and base length 8

to find the area of a base triangle, we use the formula
A+=+%281%2F2%29bh, where b is the base of the triangle, and h+is the triangle's height.
find h+is the triangle's height:h=sqrt%2818%5E2-%2818%2F2%29%5E2%29+=15.6
so, the area of a base triangle is:
A+=+%281%2F2%2918%2A15.6->A+=+140.4
SA+=+140.4%2B+%283%2F2%2918%2Al
since slant height l=sqrt%28h%5E2%2B%288%2F2%29%5E2%29=sqrt%2815.6%5E2%2B4%5E2%29=16.1
SA+=+140.4%2B+3%2A9%2A16.1
SA+=+575.1