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Question 1089128: x-y+2=4,2x+y-32=0,x+y+z=2
Answer by mrafea(1) (Show Source):
You can put this solution on YOUR website! x-y+2=4 --(1)
2x+y-32=0 --(2)
Adding both equations:
3x - 30 = 4
3x = 34
x = 34/3
Substituting x = 34/3 in equation (1):
34/3-y+2=4
y = 34/3 + 2 - 4 = 28/3
Substituting x = 34/3 and y = 28/3 in x+y+z=2:
34/3+28/3+z=2
z = 2 - 62/3 = -56/3
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