Question 1089090: What's the remainder when 2x^4 -3x^3 +4x^2 -5x+6 is divided by x-3?
A)108
B)96
C)87
D)75 Found 2 solutions by Boreal, MathTherapy:Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! ------2x^3+3x^2+13x+34
x-3/2x^4-3x^3+4x^2-5x+6
-----2x^4-6x^3 change signs
----------3x^3+4x^2-5x+6
----------3x^3-9x^2-5x+6
---------------13x^2-5x+6, after changing signs of the first two.
---------------13x^2-39x
----------------------34x+6
----------------------34x-102, change signs
remainder is 108.
A
I don't know what these people are doing on this site. I would never want them to even help my 6 year-old.
Since it's being divided by x - 3, then the remainder will be p(3).
With polynomial being , we get:
p(3) = 2(81) - 3(27) + 4(9) - 15 + 6
p(3) = 162 - 81 + 36 - 15 + 6
p(3), or
