Question 1089042: tan^2 A=3(sec A-1)
Answer by natolino_2017(77)   (Show Source):
You can put this solution on YOUR website! tan^2(A) = Sec^2(A) - 1 (Pythagorean's Theorem)
So Sec^2(A) - 1 = 3(Sec(A) - 1)
let u= Sec(A)
u^2 - 3u + 2 = 0
(u - 2)(u - 1) = 0
so u={1,2}
Sec(A) = 1 or Sec(A) = 2
A = 0 + 2k1*Pi = 2k1*Pi or (A = Pi/3 + 2k2*Pi or A =5Pi/3 + 2k3*Pi) , with k1,k2,k3 Integer
@natolino_
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