SOLUTION: log (6x-7)+log x=log5

Algebra ->  Human-and-algebraic-language -> SOLUTION: log (6x-7)+log x=log5      Log On


   



Question 1088904: log (6x-7)+log x=log5
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

log+%286x-7%29%2Blog+%28x%29=log%285%29
log+%28%286x-7%29%2Ax%29=log%285%29...if log same, we have
%286x-7%29%2Ax=5
6x%5E2-7x-5=0
6x%5E2-10x%2B3x-5=0
%286x%5E2-10x%29%2B%283x-5%29=0
2x%283x-5%29%2B%283x-5%29=0
%282x+%2B+1%29%283x+-+5%29=0
solutions:
if %282x+%2B+1%29=0=>x=-1%2F2%29-%3E+disregard+negative+solution%0D%0Aif+%7B%7B%7B%283x+-+5%29=0=>x=5%2F3
so, your solution is x=5%2F3