SOLUTION: The urn held 4 black marbles, 3 red marbles, and 6 white marbles. If three marbles are drawn randomly and the first marble drawn is white, what is the probability that the second m
Algebra ->
Probability-and-statistics
-> SOLUTION: The urn held 4 black marbles, 3 red marbles, and 6 white marbles. If three marbles are drawn randomly and the first marble drawn is white, what is the probability that the second m
Log On
Question 1088843: The urn held 4 black marbles, 3 red marbles, and 6 white marbles. If three marbles are drawn randomly and the first marble drawn is white, what is the probability that the second marble is red and the third marble is black?
a.) with replacement
b.) without replacement Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! With replacement there are 13 marbles
The probability the first is white is 6/13 and the second red is 3/13 and the third black is 4/13 for a combined probability of 72/2197
Without replacement it is 6/13*3/12*4/11=72/1716 or 6/143.
