SOLUTION: find the perimeter of a right triangle if the hypotenuse is twice as long as one of the legs and the other leg is 3
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Question 108873: find the perimeter of a right triangle if the hypotenuse is twice as long as one of the legs and the other leg is 3 Answer by edjones(8007) (Show Source):
You can put this solution on YOUR website! a^2+b^2=c^2
a^2+3^2=(2a)^2
a^2+9=4a^2
-4a^2+a^2+9=0
-3a^2+9=0
3a^2-9=0 multiply each side by -1
3(a^2-3)=0
a^2=3
a=sqrt(3), b=3, c=2sqrt(3)
perimeter=sqrt(3)+3+2sqrt(3)
= 3+3sqrt(3)
Always check:
(sqrt(3))^2+3^2=(2sqrt(3))^2
3+9=4*3 true
Ed
