SOLUTION: THE LENGTH OF A RECTANGULAR GARDEN IS 6 FT LESS THAN 5 TIMES ITS WIDTH. IF THE PERIMETER OF THE GARDEN IS 48 FT, FIND THE DEMINSIONS OF THE GARDEN. THANKS JMS

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Question 108862: THE LENGTH OF A RECTANGULAR GARDEN IS 6 FT LESS THAN 5 TIMES ITS WIDTH. IF THE
PERIMETER OF THE GARDEN IS 48 FT, FIND THE DEMINSIONS OF THE GARDEN.
THANKS
JMS
Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
L=5W-6
AREA=L*W
48=(5W-6)W
48=5W^2-6W
5W^2-6W-48=0
USING THE QUADRATIC EQUATION WE GET:
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29
W=(6+-SQRT[-6^2-4*5*-48])/2*5
W=(6+-SQRT[36+960])/10
W=(6+-SQRT996)/10
W=(6+31.56)/10
W=37.56/10
W=3.76 FOR THE WIDTH OF THE GARDEN.
L=5*3.76-6=12.8 FOR THE LENGTH OF THE GARDEN
PROOF
3.76*12.8=48
48=48