SOLUTION: Isabel is 10 years older than Marie. In 2 years, twice Isabel's age will be equal to 3 times Marie's age. How old is each now?

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Question 1088579: Isabel is 10 years older than Marie. In 2 years, twice Isabel's age will be equal to 3 times Marie's age. How old is each now?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +a+ = Isabel's age now
Let +b+ = Marie's age now
---------------------------
(1) +a+=+b+%2B+10+
(2) +2%2A%28+a+%2B+2+%29+=+3%2A%28+b+%2B+2+%29+
---------------------------------
Substitute (1) into (2)
(2) +2%2A%28+b+%2B+10+%2B+2+%29+=+3%2A%28+b+%2B+2+%29+
(2) +2%2A%28+b+%2B+12+%29+=+3%2A%28+b+%2B+2+%29+
(2) +2b+%2B+24+=+3b+%2B+6+
(2) +b+=+24+-+6+
(2) +b+=+18+
and
(1) +a+=+18+%2B+10+
(1) +a+=+28+
-----------------------
Isabel is 28
Marie is 18
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check:
(2) +2%2A%28+a+%2B+2+%29+=+3%2A%28+b+%2B+2+%29+
(2) +2%2A%28+28+%2B+2+%29+=+3%2A%28+18+%2B+2+%29+
(2) +2%2A30+=+3%2A20+
(2) +60+=+60+
OK