SOLUTION: please solve this problem : 'A circle of radius 2 is centered at the origin and goes through the point (-1, √3) a find an equation for the line goes through the point (-1,
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-> SOLUTION: please solve this problem : 'A circle of radius 2 is centered at the origin and goes through the point (-1, √3) a find an equation for the line goes through the point (-1,
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Question 1088470: please solve this problem : 'A circle of radius 2 is centered at the origin and goes through the point (-1, √3) a find an equation for the line goes through the point (-1,√3) b find an equation for he tangent line to the circle at (-1,√3) Hint: A tangent line is perpendicular to the radius at the point of tangent' Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! A circle of radius 2 is centered at the origin and goes through the point (-1,sqrt(3)) a find an equation for the line goes through the point
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There are an infinite # of them.
x = -1 is one of them.
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b find an equation for he tangent line to the circle at (-1,sqrt(3))
Slope m at any point on the circle = -x/y = sqrt(3)/3
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y - y1 = m*(x - x1)
y - sqrt(3) = (sqrt(3)/3)*(x+1)
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Hint: We don't need hints.
