SOLUTION: In a box there are 3 orange balls,4 blue balls and 5 brown balls.what is the probability of drawing three balls​ simultaneously and 1)they are of the same color? 2)they are

1.  The total number of balls is 3 + 4 + 5 = 12.

    Hence, there are    of possible outputs when you draw three balls simultaneously.

    So, your space of events counts   = 220 elements (events, outputs).

    The number of lucky events is   +  +  =  +  +  = 3+4+10 = 15.


    The probability to draw 3 balls of the same color is  = .



2.  In how many ways can you get the output of 3 different colors ?

    In 3*4*5 = 60 ways.

    Indeed, you may have any one of 3 orange balls, any one of 4 blue balls and any one of 5 brown balls- in all, 60 outputs.

    Therefore, the probability to draw 3 balls of different colors is  = .