SOLUTION: A passenger train can travel 325 mi in the same time a freight train can take to travel 200 miles. If the speed of the passenger train is 25 mi/h faster then the speed of the frei
Algebra ->
Customizable Word Problem Solvers
-> Travel
-> SOLUTION: A passenger train can travel 325 mi in the same time a freight train can take to travel 200 miles. If the speed of the passenger train is 25 mi/h faster then the speed of the frei
Log On
Question 108830: A passenger train can travel 325 mi in the same time a freight train can take to travel 200 miles. If the speed of the passenger train is 25 mi/h faster then the speed of the freight train, find the speed of each. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! A passenger train can travel 325 mi in the same time a freight train can take to travel 200 miles. If the speed of the passenger train is 25 mi/h faster then the speed of the freight train, find the speed of each.
----------
Passenger train DATA:
distance =325 miles ; rate = x mph; time = d/r = 325/x hrs.
-----------------
Freight train DATA:
distance = 200 miles ; rate = x-25 mph time = d/r = 200/(x-25) hrs
------------------
EQUATION:
time = time
325/x = 200/(x-25)
65/x = 40/(x-25)
65(x-25) = 40x
65x - 65*25 = 40x
25x = 65*25
x = 65 mph (speed of the passenger train)
x-25 = 40 mph (speed of the freight train)
=================
Cheers,
Stan H.
(