SOLUTION: The mean time from prescription drop-off to medicine pickup for a customer served at Heisenberg’s Pharmacy is 64 minutes, with a standard deviation of 18 minutes. Assuming a normal

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Question 1087745: The mean time from prescription drop-off to medicine pickup for a customer served at Heisenberg’s Pharmacy is 64 minutes, with a standard deviation of 18 minutes. Assuming a normal distribution, what is the probability that a randomly chosen customer experiences service done between 64 and 100 minutes?
Answer by mathmate(429) About Me  (Show Source):
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Question:
The mean time from prescription drop-off to medicine pickup for a customer served at Heisenberg’s Pharmacy is 64 minutes, with a standard deviation of 18 minutes. Assuming a normal distribution, what is the probability that a randomly chosen customer experiences service done between 64 and 100 minutes?

Solution:
mean=μ=64 minutes
sd=σ=18 minutes
normal distribution N(64,18)

Need P(64
P(64 =P((64-μ)/σ < z < (100-&mul)/σ)
=P((64-64)/18 < z < (100-64)/18)
=P(0 < z < 2)
=P(z<2)-P(z<0)
=0.9772499-0.5 [ from tables ]
=0.47725