Question 1087745: The mean time from prescription drop-off to medicine pickup for a customer served at Heisenberg’s Pharmacy is 64 minutes, with a standard deviation of 18 minutes. Assuming a normal distribution, what is the probability that a randomly chosen customer experiences service done between 64 and 100 minutes?
Answer by mathmate(429) (Show Source):
You can put this solution on YOUR website! Question:
The mean time from prescription drop-off to medicine pickup for a customer served at Heisenberg’s Pharmacy is 64 minutes, with a standard deviation of 18 minutes. Assuming a normal distribution, what is the probability that a randomly chosen customer experiences service done between 64 and 100 minutes?
Solution:
mean=μ=64 minutes
sd=σ=18 minutes
normal distribution N(64,18)
Need P(64
P(64
=P((64-μ)/σ < z < (100-&mul)/σ)
=P((64-64)/18 < z < (100-64)/18)
=P(0 < z < 2)
=P(z<2)-P(z<0)
=0.9772499-0.5 [ from tables ]
=0.47725
|
|
|