SOLUTION: Use algebra to determine 3 consecutive integers that add up to the largest integer less than 43.

Let x = the smallest of the three consecutive integers.
Then x+1 = the middle-sized of the three consecutive integers.
Then x+2 = the largest of the three consecutive integers.










The largest integer less than  is 13.

So the three consecutive integers are 13,14,and 15. They add to 42.

Edwin

Let smallest integer be S

Then others are: S + 1, and S + 2

The smallest INTEGER that's < 43 is 42

We then get: S + S + 1 + S + 2 = 42

3S + 3 = 42

3S = 39