SOLUTION: The width of a rectangle is 14 less than twice the length the perimeter is 32 cm what is the area of the rectangle
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Question 1087393: The width of a rectangle is 14 less than twice the length the perimeter is 32 cm what is the area of the rectangle Answer by addingup(3677) (Show Source):
You can put this solution on YOUR website! W = 2L-14
2W+2L = 32
2(2L-14)+2L = 32
4L-28+2L = 32
6L = 60
L = 10
W = 2L-14 = 2(10)-14 = 20-14 = 6
Check:
Perimeter: 2W+2L = 32; 2(6)+2(10) = 32; 12+20 = 32 Correct
