SOLUTION: Find the first, fourth, and eighth terms of the sequence: A(n)=-2*2^2-1 possible answers: -8; -64;-1,024 -2; -16;-256 1;-64;-16,384 -4;-32;-512

Algebra ->  Sequences-and-series -> SOLUTION: Find the first, fourth, and eighth terms of the sequence: A(n)=-2*2^2-1 possible answers: -8; -64;-1,024 -2; -16;-256 1;-64;-16,384 -4;-32;-512      Log On


   

Question 1087322: Find the first, fourth, and eighth terms of the sequence:
A(n)=-2*2^2-1
possible answers:
-8; -64;-1,024
-2; -16;-256
1;-64;-16,384
-4;-32;-512
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

I believe you made mistake writing 2%5E%282-1%29, should be 2%5E%28n-1%29
so,
A%28n%29=-2%2A2%5E%28n-1+%29
Find:
to find the first term, plug in 1 for n
A%281%29=-2%2A2%5E%281-1+%29
A%281%29=-2%2A2%5E%280+%29
A%281%29=-2%2A1+%29
A%281%29=-2
fourth, n=4
A%284%29=-2%2A2%5E%284-1+%29
A%284%29=-2%2A2%5E%283+%29
A%284%29=-2%2A8+%29
A%284%29=-16

and eighth term, n=8
A%288%29=-2%2A2%5E%288-1+%29
A%288%29=-2%2A2%5E%287+%29
A%288%29=-2%2A128+%29
A%288%29=-256

and, your answer is: -2; -16;-256