SOLUTION: What is the standard form of 4x^2+4y^2-16x+40y+67=0

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Question 1087142: What is the standard form of 4x^2+4y^2-16x+40y+67=0
Answer by MathLover1(20850) About Me  (Show Source):
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the standard form of
4x%5E2%2B4y%5E2-16x%2B40y%2B67=0+..........complete squares
%284x%5E2-16x%29%2B%284y%5E2%2B40y%29%2B67=0+
4%28x%5E2-4x%2Bb%5E2%29-4b%5E2%2B4%28y%5E2%2B10y%2Bb%5E2%29-4b%5E2%2B67=0+
4%28x%5E2-4x%2B2%5E2%29-4%2A2%5E2%2B4%28y%5E2%2B10y%2B5%5E2%29-4%2A5%5E2%2B67=0+
4%28x-2%29%5E2-16%2B4%28y%2B5%29%5E2-100%2B67=0+
4%28x-2%29%5E2%2B4%28y%2B5%29%5E2-49=0+
4%28x-2%29%5E2%2B4%28y%2B5%29%5E2=49+
%28x-2%29%5E2%2B%28y%2B5%29%5E2=49%2F4