SOLUTION: Marita can prepare the payroll in 6 hours. If charles help her, they can finish it in 4 hours. How long would it take charles to do the job alone?

Algebra ->  Rate-of-work-word-problems -> SOLUTION: Marita can prepare the payroll in 6 hours. If charles help her, they can finish it in 4 hours. How long would it take charles to do the job alone?      Log On


   



Question 1087137: Marita can prepare the payroll in 6 hours. If charles help her, they can finish it in 4 hours. How long would it take charles to do the job alone?
Found 2 solutions by jorel1380, ikleyn:
Answer by jorel1380(3719) About Me  (Show Source):
You can put this solution on YOUR website!
Marita can prepare the payroll in 6 hours. Therefore, she does 1/6th of the payroll per hour. Let c be the time in takes charles to do the job alone. Then:
1/6+1/c=1/4
2c+12=3c
c=12
It takes Charles 12 hours to do the payroll alone.
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Answer by ikleyn(52835) About Me  (Show Source):
You can put this solution on YOUR website!
.
Their combined rate of work is 1%2F4 of the job per hour.

Marita's individual rate of work is 1%2F6 of the job per hour.

Hence, Charles' individual rate of work is 1%2F4-1%2F6 = 3%2F12-2%2F12 = 1%2F12 of the job per hour.


It means that Charles can complete the job in 12 hours working alone.


It is a typical joint work problem.

There is a wide variety of similar solved joint-work problems with detailed explanations in this site. See the lessons
    - Using Fractions to solve word problems on joint work
    - Solving more complicated word problems on joint work
    - Selected joint-work word problems from the archive


Read them and get be trained in solving joint-work problems.

Also, you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this textbook under the topic "Rate of work and joint work problems" of the section "Word problems".