SOLUTION: I'm trying to figure out how to get the E alone in this equation. R=(2/3)log E-3

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Question 1087097: I'm trying to figure out how to get the E alone in this equation. R=(2/3)log E-3
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
IF you have this:
R=%282%2F3%29log%28+E%29-3+
R%2B3=%282%2F3%29log%28+E%29+
%28R%2B3%29%2F%282%2F3%29=log%28+E%29+
3%28R%2B3%29%2F2=log%28+E%29+
log%28+E%29=+3%28R%2B3%29%2F2.....since y+=+log%28b%2Cx%29 is equivalent to x+=+b%5Ey, and in your case y+=%283R%2B9%29%2F2, base b=10, and x=E
so, you will have:

highlight%28E=10%5E%283%28R%2B3%29%2F2%29%29