SOLUTION: the sum of three integers is 82. the sum of the first and second integers exceeds the third by 86. the third integer is 61 less than the first. find the three integers
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Question 1087068: the sum of three integers is 82. the sum of the first and second integers exceeds the third by 86. the third integer is 61 less than the first. find the three integers Answer by math_helper(2461) (Show Source):
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Answer: , , and
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Workout:
A + B + C = 82 (1)
A + B = C + 86 (2)
C = A - 61 (3)
I chose to substitute "C+86" from (2) as "A+B" in (1):
(C + 86) + C = 82 ==> 2C = -4 ==> C = -2
Plugging this result into (3) gives A = 59
Plugging the newly found A & C values into (1) or (2) gives B = 25
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Check: A + B + C = 59 + 25 - 2 = 82 (ok)
A + B = 59 + 25 = 84 and C + 86 = -2 + 86 = 84 (ok)
C = -2 and A-61 = 59-61 = -2 (ok)