SOLUTION: Find the sum of this series: 3 + 6 + 12 + 24 + 48 + …; 10th term. a. 6742 b. 2455 c. 3069

Algebra ->  Finance -> SOLUTION: Find the sum of this series: 3 + 6 + 12 + 24 + 48 + …; 10th term. a. 6742 b. 2455 c. 3069      Log On


   



Question 1086937: Find the sum of this series: 3 + 6 + 12 + 24 + 48 + …; 10th term.
a. 6742
b. 2455
c. 3069

Found 2 solutions by MathLover1, MathTherapy:
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

3 + 6 + 12 + 24 + 48 + …..; 10th term.
rule: 3%2A2%5En where n=0,1,...
3%2A2%5E0
6=3%2A2%5E1
12=3%2A2%5E2
24=3%2A2%5E3
48=3%2A2%5E4
now find next terms up to 10th
3%2A2%5E5=96
3%2A2%5E6=192
3%2A2%5E7=384
3%2A2%5E8=768
3%2A2%5E9=1536
---------------------
add all:
3+%2B+6+%2B+12+%2B+24+%2B+48+%2B96%2B192%2B384%2B768%2B1536=3069
your answer is:
c. 3069

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
Find the sum of this series: 3 + 6 + 12 + 24 + 48 + …; 10th term.
a. 6742
b. 2455
c. 3069
Sum of a GP, or matrix%281%2C3%2C+S%5Bn%5D%2C+%22=%22%2C+a%5B1%5D+%2A+%28%281+-+r%5En%29%2F%281+-+r%29%29%29, with:
S%5Bn%5D = Sum of "n" terms (Unknown, in this case)
a%5B1%5D = 1st term (3, in this case)
r = Common ratio (2, in this case)
n = Number of terms (10, in this case)
matrix%281%2C3%2C+S%5Bn%5D%2C+%22=%22%2C+a%5B1%5D+%2A+%28%281+-+r%5En%29%2F%281+-+r%29%29%29 then becomes: matrix%281%2C3%2C+S%5B10%5D%2C+%22=%22%2C+3+%2A+%28%281+-+2%5E10%29%2F%281+-+2%29%29%29, and then: