SOLUTION: Find the excluded values for the algebraic fraction. x+6/x^2+3x-18

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Question 1086869: Find the excluded values for the algebraic fraction.
x+6/x^2+3x-18

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

%28x%2B6%29%2F%28x%5E2%2B3x-18%29
the excluded values for the algebraic fraction will be values that make denominator equal to zero
so, find x that makes x%5E2%2B3x-18=0
x%5E2%2B3x-18=0...factor
x%5E2%2B6x-3x-18=0
%28x%5E2%2B6x%29-%283x%2B18%29=0
x%28x%2B6%29-3%28x%2B6%29=0
%28x+-+3%29%28x+%2B+6%29+=+0
solutions:
if %28x+-+3%29+=+0=>x=3
if %28x+%2B+6%29+=+0=>x=-6
so, the excluded values for the algebraic fraction will be x=3 and x=-6