SOLUTION: If x^2 + 1/x^2 =102, find the value of x^3 - 1/x^3

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Question 1086799: If x^2 + 1/x^2 =102, find the value of x^3 - 1/x^3
Found 2 solutions by rothauserc, ikleyn:
Answer by rothauserc(4718) About Me  (Show Source):
You can put this solution on YOUR website!
x^2 + 1/x^2 = 102
:
x^4 + 1 = 102x^2, for x not = 0
:
x^4 -102X^2 +1 = 0
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let u = x^2, then
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u^2 -102u = -1
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complete the square
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u^2 -102u + 2601 = 2601 -1
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(u -51)^2 = 2600
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take square root of both sides of =
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u - 51 = 50.99
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u = 51 + 50.99 = 101.99
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u = x^2, then
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x^2 = 101.99
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x = + or - 10.099
:
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x^3 - 1/x^3 = ?
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1) (10.099)^3 - 1/(10.099)^3 = 1029.994
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2) (-10.099)^3 - 1/(-10.099)^3 = −1029.994
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check answers for x
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x^2 + 1/x^2 = 102
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(10.099)^2 + 1/(10.099)^2 = 102
101.999 = 102
:
(-10.099)^2 + 1/(-10.099)^2 = 102
101.999 = 102
:
our answer checks
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Answer by ikleyn(52787) About Me  (Show Source):
You can put this solution on YOUR website!
.
If x%5E2+%2B+1%2Fx%5E2 = 102,  then  x%5E2 - 2 + 1%2Fx%5E2%29 = 102 - 2 = 100, 

or  %28x-1%2Fx%29%5E2 = 100,  which implies   x+-+1%2Fx = 10  or  x-1%2Fx = -10.


If  x+-+1%2Fx = 10  then

    %28x+-+1%2Fx%29%5E3 = 1000 = x%5E3+-+3x%5E2%2A%281%2Fx%29+%2B+3x%2A%281%2Fx%5E2%29+-+1%2Fx%5E3 = %28x%5E3+-1%2Fx%5E3%29 - %283x+-+3%2Fx%29 = %28x%5E3+-+1%2Fx%5E3%29 - 3%2A%28x-1%2Fx%29 = %28x%5E3+-+1%2Fx%5E3%29 - 3*10.


It implies  %28x%5E3+-+1%2Fx%5E3%29 = 1030.



If  x+-+1%2Fx = -10  then

    %28x+-+1%2Fx%29%5E3 = -1000 = x%5E3+-+3x%5E2%2A%281%2Fx%29+%2B+3x%2A%281%2Fx%5E2%29+-+1%2Fx%5E3 = %28x%5E3+-1%2Fx%5E3%29 - 3x+-+3%2Fx%29 = %28x%5E3+-+1%2Fx%5E3%29 - 3%2A%28x-1%2Fx%29 = %28x%5E3+-+1%2Fx%5E3%29 - 3*(-10) = %28x%5E3+-+1%2Fx%5E3%29 + 30.


It implies  %28x%5E3+-+1%2Fx%5E3%29 = -1000 - 30 = -1030.

Answer.  Under the given condition,  the expression  %28x%5E3+-+1%2Fx%5E3%29  may have two values:  1030  or  -1030.


Solved.


Two lessons to learn from this solution

    1.  You do not need to solve equations to get the answer.

    2.  The approach the tutor @rothauserc took to solve the problem is WRONG.