SOLUTION: Solve for the standard form and general form and the other parts of the parabola with the given conditions: 1.) The minimum point is -2 and 6. 2.) passing through points (2,8).

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Solve for the standard form and general form and the other parts of the parabola with the given conditions: 1.) The minimum point is -2 and 6. 2.) passing through points (2,8).      Log On


   

Question 1086788: Solve for the standard form and general form and the other parts of the parabola with the given conditions:
1.) The minimum point is -2 and 6.
2.) passing through points (2,8).
Answer by josgarithmetic(39631) About Me  (Show Source):
You can put this solution on YOUR website!
y=a%28x%2B2%29%5E2%2B6

y-6=a%28x%2B2%29%5E2

a=%28y-6%29%2F%28x%2B2%29%5E2

Use given point on the parabola:
a=%288-6%29%2F%282%2B2%29%5E2

a=2%2F16

a=1%2F8

y=%281%2F8%29%28x%2B2%29%5E2%2B6
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