Question 1086694: According to a report from the Center for Studying Health System Change, 20% of Americans delay or go without medical care because of concerns about cost (The Wall Street Journal, June 26, 2008). Suppose eight individuals are randomly selected.
What is the probability that no more than two will delay or go without medical care? (Do not round intermediate calculations. Round your final answers to 4 decimal places.)
What is the probability that at least seven will delay or go without medical care? (Do not round intermediate calculations. Round your final answers to 4 decimal places.)
What is the expected number of individuals who will delay or go without medical care? (Do not round intermediate calculations. Round your final answers to 4 decimal places.)
Calculate the variance and the standard deviation for this probability distribution. (Do not round intermediate calculations. Round your final answers to 4 decimal places.)
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! According to a report from the Center for Studying Health System Change, 20% of Americans delay or go without medical care because of concerns about cost (The Wall Street Journal, June 26, 2008).
Suppose eight individuals are randomly selected.
----------
What is the probability that no more than two will delay or go without medical care? (Do not round intermediate calculations. Round your final answers to 4 decimal places.)
Binomial Problem with n = 8 and p = 0.2
P(0<= x <= 1) = binomcdf(8,0.2,1) = 0.5033
------------------------------------------
What is the probability that at least seven will delay or go without medical care? (Do not round intermediate calculations. Round your final answers to 4 decimal places.)
P(7<= x <=8) = 1 - binomcdf(8,0.2,6) = 0.00008
-------------------------------------------------
What is the expected number of individuals who will delay or go without medical care? (Do not round intermediate calculations. Round your final answers to 4 decimal places.)
E(x) = n*p = 8*0.2 = 1.6
-------------------------------------
Calculate the variance and the standard deviation for this probability distribution. (Do not round intermediate calculations. Round your final answers to 4 decimal places.)
var(x) = npq = 8*0.2*0.8 = 1.28
std(x) = sqrt(npq) = sqrt(1.28) = 1.1314
------------------------
Cheers,
Stan H.
----------
|
|
|
