SOLUTION: A chemical store room has a 90% acid solution and 40% solution. How many CENTILITERS of the 90% solution should be added to 50 CENTILITERS of the 40% solution to yield up a 50% sol

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Question 1086552: A chemical store room has a 90% acid solution and 40% solution. How many CENTILITERS of the 90% solution should be added to 50 CENTILITERS of the 40% solution to yield up a 50% solution?
p.s. i caps the centiliters for clearer comprehension. Thank you sir/maam tutors! :)

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Let x = amount of the 90% acid solution (in centiliters)

We have 50 centiliters of the 40% solution.
This means we have 0.4*50 = 20 centiliters of pure acid

We're adding on x more centiliters of the 90% solution.
There are an additional 0.9*x centiliters of pure acid.

In total, we have 0.9*x+20 centiliters of pure acid.

This is out of x+50 centiliters of solution.

Divide the expressions 0.9*x + 20 over x+50 to get %280.9%2Ax+%2B+20%29%2F%28x%2B50%29.
This fraction represents the ratio of pure acid to total solution.
We want this ratio to be equal to 50%.
This is because we want the final solution to be 50% acid

So set %280.9%2Ax+%2B+20%29%2F%28x%2B50%29 equal to 0.50 to get %280.9%2Ax+%2B+20%29%2F%28x%2B50%29+=+0.50

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Now solve for x

%280.9%2Ax+%2B+20%29%2F%28x%2B50%29+=+0.50

0.9x+%2B+20+=+0.50%28x%2B50%29

0.9x+%2B+20+=+0.50%28x%29%2B0.50%2A%2850%29

0.9x+%2B+20+=+0.50x%2B25

0.9x+%2B+20-0.50x+=+0.50x%2B25-0.50x

0.4x+%2B+20+=+25

0.4x+%2B+20-20+=+25-20

0.4x+=+5

%280.4x%29%2F%280.4%29+=+%285%29%2F%280.4%29

x+=+12.5

We need 12.5 (12 and a half) centiliters of the 90% solution.