SOLUTION: The stopping distance, d, of a particular car after the brakes are applied varies directly as the dquare of the rate, r. If the car is traveling 25mph, if can stop in 50ft. How m

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: The stopping distance, d, of a particular car after the brakes are applied varies directly as the dquare of the rate, r. If the car is traveling 25mph, if can stop in 50ft. How m      Log On


   



Question 1086419: The stopping distance, d, of a particular car after the brakes are applied varies directly as the dquare of the rate, r. If the car is traveling 25mph, if can stop in 50ft. How many feet wil it take the same car to stop when it is traveling 50mph?
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
The stopping distance, d, of a particular car after the brakes are applied varies directly as the square of the rate, r. If the car is traveling 25mph, if can stop in 50ft. How many feet will it take the same car to stop when it is traveling 50mph?
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d = k*r^2, k is a constant.
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50 = k*25^2 = 625k
k = 50/625 = 2/25
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At 50 mi/hr:
d = k*50^2 = 2500k
d = 200 feet