SOLUTION: a jet aircraft traveled 1416 miles from the Atlanta to El Paso. traveling Against the Wind to trip take 3.2 hours. the return trip with the wind takes 2.4 hours. find the speed of
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Question 1086393: a jet aircraft traveled 1416 miles from the Atlanta to El Paso. traveling Against the Wind to trip take 3.2 hours. the return trip with the wind takes 2.4 hours. find the speed of the aircraft in the still air and the speed of the wind. Answer by ikleyn(52884) (Show Source):
The equations are
u - v = (1) (effective speed flying against the wind)
u + v = (2) (effective speed flying with the wind)
where "u" is the aircraft speed at no wind and "v" is the speed of wind.
Simplify (1) and (2):
u - v = 442.5 (3)
u + v = 590. (4)
Add equations (3) and (4). You will get
2u = 1032.5 ----> u = = 516.25.
Thus we found the speed of the aircraft at no wind. It is 516.25 mph.
Now from equation (4) v = 590 - 516.25 = 73.75 mph.
Answer. the speed of the aircraft at no wind is 516.25 mph. The speed of wind is 73.75 mph.
Solved.
It is a typical "tailwind and headwind" word problem.
