SOLUTION: can someone help me with this please thank you.solve the equation in [0,2pi] using any appropriate method.answer in exact form. 10tan(pi/2-x)sin^2x=5sqrt3/2

Algebra ->  Trigonometry-basics -> SOLUTION: can someone help me with this please thank you.solve the equation in [0,2pi] using any appropriate method.answer in exact form. 10tan(pi/2-x)sin^2x=5sqrt3/2       Log On


   



Question 1086310: can someone help me with this please thank you.solve the equation in [0,2pi] using any appropriate method.answer in exact form.
10tan(pi/2-x)sin^2x=5sqrt3/2

Answer by ikleyn(52814) About Me  (Show Source):
You can put this solution on YOUR website!
.
First thing you need to know and to apply is  tan%28x-pi%2F2%29 = cot(x) = cos%28x%29%2Fsin%28x%29.


When you apply it, your equation becomes


10%2A%28cos%28x%29%2Fsin%28x%29%29%2Asin%5E2%28x%29 = 5%2A%28sqrt%283%29%2F2%29,   or

2%2Acos%28x%29%2Asin%28x%29 = sqrt%283%29%2F2.


Second thing you need to know is  2*cos(x)*sin(x) = sin(2x).


When you apply it, the last equation becomes


sin(2x) = sqrt%283%29%2F2.


It has the solutions  2x = pi%2F3,  2x = 2pi%2F3,  2x = pi%2F3+%2B+2pi  and  2x = %282pi%29%2F3+%2B+2pi.


Therefore, the solutions for x are  pi%2F6,  pi%2F3,  7pi%2F6  and  %284pi%29%2F3.

Solved.