SOLUTION: please help thank you . a projectile is launched from a catapult with initial velocity 350ft/sec at an angle of 65 degrees assume that the projectile is launched in ground level. F

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: please help thank you . a projectile is launched from a catapult with initial velocity 350ft/sec at an angle of 65 degrees assume that the projectile is launched in ground level. F      Log On


   

Question 1085869: please help thank you . a projectile is launched from a catapult with initial velocity 350ft/sec at an angle of 65 degrees assume that the projectile is launched in ground level. Find the position of the object after 4 sec.
Answer by ikleyn(52772) About Me  (Show Source):
You can put this solution on YOUR website!
.
x(t) = V%5B0%5D%2Acos%28alpha%29%2At         = 350*cos(65°)*4       =  592.4 ft.

y(t) = -16%2At%5E2%2BV%5B0%5D%2Asin%28alpha%29%2At = -16*4^2 + sin(65°)*4 = 1012.5 ft.