SOLUTION: find the x-intercepts of the parabola with vertex (-3,16) and y-intercept (0,-20). Write your answer in this form: (x1,y1),(x2,y2). If necessary, round to the nearest hundredth

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: find the x-intercepts of the parabola with vertex (-3,16) and y-intercept (0,-20). Write your answer in this form: (x1,y1),(x2,y2). If necessary, round to the nearest hundredth      Log On


   



Question 1085857: find the x-intercepts of the parabola with vertex (-3,16) and y-intercept (0,-20). Write your answer in this form: (x1,y1),(x2,y2). If necessary, round to the nearest hundredth
Found 2 solutions by josmiceli, MathTherapy:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
The general formula is:
+y+=+a%2Ax%5E2+%2B+b%2Ax+%2B+c+
The formula for the vertex is:
+x%5Bv%5D+=+-b%2F%282a%29+
---------------------------
You are given 2 points:
( -3,16 )
( 0, -20 )
Plug these values into the general formula
(-3,16)
+16+=+a%2A%28-3%29%5E2+%2B+b%2A%28-3%29+%2B+c+
+9a+-+3b+%2B+c+=+16+
(0,-20)
+-20+=+a%2A0%5E2+%2B+b%2A0+%2B+c+
+c+=+-20+
------------
Now the equation is:
+y+=+a%2Ax%5E2+%2B+b%2Ax+-+20+
Al;so:
+x%5Bv%5D+=+-b%2F%282a%29+
+x%5Bv%5D+=+-3+ ( given )
+-3+=+-b%2F%282a%29+
+-b+=+-6a+
+b+=+6a+
So, now I have:
+y+=+a%2Ax%5E2+%2B+%286a%29%2Ax+-+20+
also
+y%5Bv%5D+=+16+ ( given )
+16+=+a%2A%28-3%29%5E2+%2B+%286a%29%2A%28-3%29+-+20+
+16+=+9a+-+18a+-+20+
+-9a+=+36+
+a+=+-4+
and
+b+=+6a+
+b+=+-24+
so, the equation is:
+y+=+-4x%5E2+-+24x+-+20+
----------------------------
Find the roots:
x%5B1%5D+=+%28-b+%2B+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
x%5B1%5D+=+%28-%28-24%29+%2B+sqrt%28+%28-24%29%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
x%5B1%5D+=+%28+24+%2B+sqrt%28+576+-+4%2A%28-4%29%2A%28-20%29+%29%29%2F%282%2A%28-4%29%29+
x%5B1%5D+=+%28+24+%2B+sqrt%28+576+-+320+%29%29%2F%28-8%29+
x%5B1%5D+=+%28+24+%2B+sqrt%28+256+%29%29%2F%28-8%29+
x%5B1%5D+=+%28+24+%2B+16+%29%2F%28-8%29+
x%5B1%5D+=+40%2F%28-8%29+
x%5B1%5D+=+-5+
----------------
The other root is at:
+x%5B2%5D+=+%28+24+-+16+%29%2F%28-8%29+
+x%5B2%5D+=+8%2F%28-8%29+
+x%5B2%5D+=+-1+
The x-intercepts are:
( -5,0 ) and ( -1,0 )
-----------------------
Here's the plot:
+graph%28+400%2C+400%2C+-10%2C+2%2C+-5%2C+20%2C+-4x%5E2+-+24x+-+20+%29+
check the math and get an other opinion if needed

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

find the x-intercepts of the parabola with vertex (-3,16) and y-intercept (0,-20). Write your answer in this form: (x1,y1),(x2,y2). If necessary, round to the nearest hundredth
y+=+a%28x+-+h%29%5E2+%2B+k <===== Vertex form of a parabolic equation
-+20+=+a%280+-+-+3%292+%2B+16 ------- Substituting (0, - 20) for (x, y) and (- 3, 16) for (h, k)
- 20 = 9a + 16
- 20 - 16 = 9a
- 36 = 9a
matrix%281%2C5%2C+%28-+36%29%2F9%2C+%22=%22%2C+a%2C+%22=%22%2C+-+4%29

y+=+a%28x+-+h%29%5E2+%2B+k <===== Vertex form of a parabolic equation
0+=+-+4%28x+-+-+3%29%5E2+%2B+16 ------- Substituting 0 for y,  - 4 for a, and (- 3, 16) for (h, k)
0+=+-+4%28x+%2B+3%29%5E2+%2B+16
0+=+-+4%28x%5E2+%2B+6x+%2B+9%29+%2B+16
0+=+-+4x%5E2+-+24x+-+36+%2B+16
0+=+-+4x%5E2+-+24x+-+20
-+4%280%29+=+-+4%28x%5E2+%2B+6x+%2B+5%29
x%5E2+%2B+6x+%2B+5+=+0
(x + 5)(x + 1) = 0
x = - 5		OR    		 x = - 1