SOLUTION: In a list of n consecutive odd numbers, the number
of terms equals the first term. If six times the sum
of the n numbers exceeds the square of their average
by 2013 times the
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-> SOLUTION: In a list of n consecutive odd numbers, the number
of terms equals the first term. If six times the sum
of the n numbers exceeds the square of their average
by 2013 times the
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Question 1085838: In a list of n consecutive odd numbers, the number
of terms equals the first term. If six times the sum
of the n numbers exceeds the square of their average
by 2013 times the average, what is the value of the
first term? Answer by Edwin McCravy(20065) (Show Source):
You can put this solution on YOUR website! In a list of n consecutive odd numbers, the number
of terms equals the first term. If six times the sum
of the n numbers exceeds the square of their average
by 2013 times the average, what is the value of the
first term?
consecutive odd numbers,
the number of terms equals the first term.
Substituting those and simplifying
If six times the sum of the n numbers exceeds the
square of their average by 2013 times the average,
Divide through by (2n-1), which cannot be 0,
since n cannot be 1/2.
First term =
Edwin
