Question 1085787: Assume that the stopping distance of a van varies directly with the square of the speed. A van traveling 20 miles per hour can stop in 30 feet. If the van is traveling 28 miles per hour, what is its stopping distance?
If the van is traveling 28 miles per hour, the stopping distance
Answer by htmentor(1343)   (Show Source):
You can put this solution on YOUR website! Since the distance varies as the square of the speed, we can express this relationship as:
d = k*s^2 where k = a constant
For two sets of distances and speeds (d1,s1) and (d2,s2) we can write
d1 = k*s1^2 and
d2 = k*s2^2
Thus d1/s1^2 = d2/s2^2 -> d2 = d1*(s2/s1)^2
Putting in the values, we have
d2 = 30*(28/20)^2 = 58.8 ft
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